document.write( "Question 56764: 6. Carla invested $14,000, part at 9% and part at 12%. If the total interest at the end of the year is $1,290, how much did she invest at 9%?
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document.write( "A) $1,000
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document.write( "B) $14,000
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document.write( "C) $13,000
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document.write( "D) $12,000
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document.write( "no book Thanks so very very much fro your time!! \n" );
document.write( "
Algebra.Com's Answer #38553 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! .09X+.12(14000-X)=1290 \n" ); document.write( ".09X+1680-.12X=1290 \n" ); document.write( "-.03X=1290-1680 \n" ); document.write( "-.03X=-390 \n" ); document.write( "X=-390/-.03 \n" ); document.write( "X=13000 AMOUNT INVESTED @ 8% \n" ); document.write( "PROOF \n" ); document.write( ".09*13000+.12(14000-13000)=1290 \n" ); document.write( "1170+.12*1000=1290 \n" ); document.write( "1170+120=1290 \n" ); document.write( "1290=1290 \n" ); document.write( " \n" ); document.write( " |