document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=612335>Question 612335</A>: <I><SPAN STYLE=\"word-break: break-all;\"> N=No(1/2)^t/16 where No=the number of grams present initially & t=the elapsed time <BR>\n" );
document.write( "in years. If 8.0g were present initially,how many grams will remain after 48 years?<BR>\n" );
document.write( "Im lost in this problem....choices are<BR>\n" );
document.write( "A.1 gram<BR>\n" );
document.write( "B.2 grams<BR>\n" );
document.write( "C.4 grams<BR>\n" );
document.write( "D.None of the above </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #385382 by </B><A HREF=/tutors/aboutme.mpl?userid=flame8855><B>flame8855(424)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=flame8855><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=flame8855><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=385382\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> = 8(1/2)^3 = 1<BR>\n" );
document.write( "so the answer is A.1 gram </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );