document.write( "Question 612143: 6 men can dig a trench in 3 days. How many days will it take 9 men to dig the same trench at the same rate? \n" ); document.write( "
Algebra.Com's Answer #385309 by Edwin McCravy(20056)![]() ![]() You can put this solution on YOUR website! 6 men can dig a trench in 3 days. How many days will it take 9 men to dig the same trench at the same rate?\r \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "\r\n" ); document.write( "Since 6 men can dig a trench in 3 days, 3 times as many men, or 18 men,\r\n" ); document.write( "can do it in 1/3 the time or just 1 day.\r\n" ); document.write( "\r\n" ); document.write( "So half of 18 men, or 9 men, will take twice as long as 18 men, or 2 days.\r\n" ); document.write( "\r\n" ); document.write( "--------------------------------------------------------\r\n" ); document.write( "\r\n" ); document.write( "Another way to do it is that this fraction must stay constant:\r\n" ); document.write( "\r\n" ); document.write( "WORKERS × TIME WORKERS × TIME\r\n" ); document.write( "—————————————— = —————————————— \r\n" ); document.write( " JOBS JOBS\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " 6 × 3 9 × T \r\n" ); document.write( " ————— = ————————\r\n" ); document.write( " 1 1\r\n" ); document.write( "\r\n" ); document.write( " 18 9T \r\n" ); document.write( " ——— = —————\r\n" ); document.write( " 1 1\r\n" ); document.write( " \r\n" ); document.write( " 18 = 9T\r\n" ); document.write( "\r\n" ); document.write( " 2 = T\r\n" ); document.write( "\r\n" ); document.write( " \r\n" ); document.write( "2 days.\r\n" ); document.write( "\r\n" ); document.write( "Edwin \n" ); document.write( " \n" ); document.write( " |