document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=56780>Question 56780</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A plane flies 500 miles with the wind and 340 miles against the wind in the same length of time.  If the speed of the wind is 28mph, what is the speed of the plane in still air? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #38529 by </B><A HREF=/tutors/aboutme.mpl?userid=Nate><B>Nate(3500)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Nate><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=38529\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> rate of air = a<BR>\n" );
document.write( "going with wind ~> 28 + a<BR>\n" );
document.write( "going against wind ~> 28 - a<BR>\n" );
document.write( "Rate*Time = Distance<BR>\n" );
document.write( "Distance/Rate = Time<BR>\n" );
document.write( "500/(28 + a) = 340/(28 - a) Since the times are equivalent, you would would equal them together.<BR>\n" );
document.write( "500(28 - a) = 340(28 + a)<BR>\n" );
document.write( "14000 - 500a = 9520 + 340a<BR>\n" );
document.write( "-840a = -4480<BR>\n" );
document.write( "a = 16/3<BR>\n" );
document.write( "Speed in still air is about 5.3333 mi/hr. We do not know the time measurement, but we can guess or propose it is in hours. The time comes to 15 hours. </SPAN>\n" );
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