document.write( "Question 612071: Solve: log(base 2) x - 2log(base2) (x-1) = 1 \n" ); document.write( "
Algebra.Com's Answer #385276 by lwsshak3(11628)\"\" \"About 
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Solve: log(base 2) x - 2log(base2) (x-1) = 1
\n" ); document.write( "log2(x)-2log2(x-1)=1
\n" ); document.write( "log2[x/(x-1)^2]=1
\n" ); document.write( "convert to exponential form
\n" ); document.write( "2^1=[x/(x-1)^2=2
\n" ); document.write( "2(x-1)^2]=x
\n" ); document.write( "2(x^2-2x+1)=x
\n" ); document.write( "2x^2-4x+2=x
\n" ); document.write( "2x^2-5x+2=0
\n" ); document.write( "(2x-1)(x-2)=0
\n" ); document.write( "x=1/2 (reject,(x-1)>0)
\n" ); document.write( "or
\n" ); document.write( "x=2
\n" ); document.write( "
\n" );