document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=611947>Question 611947</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Dad is 6 times as old as Michael and he will be 4 times as old as Michael in 4 years time. If dad is less than 60 years of age, how old will he be in 6 year's time? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #385216 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=385216\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> d = Dad's age<BR>\n" );
document.write( "m - Michael's age<BR>\n" );
document.write( ":<BR>\n" );
document.write( "Dad is 6 times as old as Michael<BR>\n" );
document.write( "d = 6m<BR>\n" );
document.write( ":<BR>\n" );
document.write( " and he will be 4 times as old as Michael in 4 years time.<BR>\n" );
document.write( "d + 4 = 4(m+4)<BR>\n" );
document.write( "d + 4 = 4m + 16<BR>\n" );
document.write( "d = 4m + 16 - 4<BR>\n" );
document.write( "d = 4m + 12<BR>\n" );
document.write( "replace d with 6m<BR>\n" );
document.write( "6m = 4m + 12<BR>\n" );
document.write( "6m - 4m = 12<BR>\n" );
document.write( "2m = 12<BR>\n" );
document.write( "m = 6 yrs is M's age<BR>\n" );
document.write( "then<BR>\n" );
document.write( "6*6 = 36 yrs is Dad's age<BR>\n" );
document.write( ":<BR>\n" );
document.write( " If dad is less than 60 years of age, how old will he be in 6 year's time?<BR>\n" );
document.write( "36 + 6 = 42 yrs  </SPAN>\n" );
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