document.write( "Question 611936: a painting measuring 12 inches by 18 inches is surrounded by a frame of uniform width. if the combined area of the painting and the frame is 432 square inches, determine the width of the frame
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Algebra.Com's Answer #385214 by nerdybill(7384)\"\" \"About 
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a painting measuring 12 inches by 18 inches is surrounded by a frame of uniform width. if the combined area of the painting and the frame is 432 square inches, determine the width of the frame
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\n" ); document.write( "Let w = width of frame
\n" ); document.write( "then
\n" ); document.write( "(12+2w)(18+2w) = 432
\n" ); document.write( "216+24w+36w+4w^2 = 432
\n" ); document.write( "216+60w+4w^2 = 432
\n" ); document.write( "4w^2+60w+216 = 432
\n" ); document.write( "4w^2+60w-216 = 0
\n" ); document.write( "w^2+15w-54 = 0
\n" ); document.write( "(w+18)(w-3) = 0
\n" ); document.write( "w = {-18,3}
\n" ); document.write( "throw out the negative solution (extraneous) leaving:
\n" ); document.write( "w = 3 inches
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