document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=611962>Question 611962</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this equation: use the laws of logarithms to solve this equation. \r<BR>\n" );
document.write( "\n" );
document.write( "ln(3-x)=ln(3x-x^2) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #385209 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=385209\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> ln(3-x)=ln(3x-x^2)<BR>\n" );
document.write( "3-x = 3x-x^2<BR>\n" );
document.write( "-x+3 = 3x-x^2<BR>\n" );
document.write( "x^2-x+3 = 3x<BR>\n" );
document.write( "x^2-4x+3 = 0<BR>\n" );
document.write( "(x-1)(x-3) = 0<BR>\n" );
document.write( "x = {1,3}<BR>\n" );
document.write( "since you can't take ln(0), we determine that x=3 is an extraneous solution -- throw it out leaving:<BR>\n" );
document.write( "x = 1 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );