document.write( "Question 611894: Find the equation of the straight line through the point (-1,-7) and parallel to y= 2x + 3 \n" ); document.write( "
Algebra.Com's Answer #385182 by Maths68(1474)\"\" \"About 
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Equation of the line slope-intercept form
\n" ); document.write( "y=mx+b
\n" ); document.write( "Equation of the Given line
\n" ); document.write( "y=2x+3
\n" ); document.write( "Compare with the equation of line slope-intercept form
\n" ); document.write( "Slope of the given = m = 2
\n" ); document.write( "Since lines are parallel their slope will be same
\n" ); document.write( "Slope of the required line = m = 2
\n" ); document.write( "Point (-1, -7)
\n" ); document.write( "We have a point and slope we can get easily the require line equation.
\n" ); document.write( "Use Equation of the line point-slope form
\n" ); document.write( "m = y2-y1/x2-x1
\n" ); document.write( "Put the values in above equation, we have
\n" ); document.write( "2=(y-(-7))/(x-(-1))
\n" ); document.write( "2=(y+7))/(x+1))
\n" ); document.write( "2(x+1)=y+7
\n" ); document.write( "2x+2=y+7
\n" ); document.write( "2x+2-7=y
\n" ); document.write( "2x-5=y
\n" ); document.write( "y=2x-5
\n" ); document.write( "Above equation is the equation of the required line\r
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\n" ); document.write( "\n" ); document.write( "Graph
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\n" ); document.write( "y=2x+3 Given line (Red)
\n" ); document.write( "y=2x-5 Required line (Green)\r
\n" ); document.write( "\n" ); document.write( "\"+graph%28500%2C500%2C-10%2C10%2C-10%2C10%2C2x%2B3%2C2x-5%29+\"
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