document.write( "Question 611752: Verify the identity with steps: (sin3x)/(sinxcosx)=4cosx-secx \n" ); document.write( "
Algebra.Com's Answer #385159 by lwsshak3(11628)\"\" \"About 
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Verify the identity with steps: (sin3x)/(sinxcosx)=4cosx-secx
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\n" ); document.write( "Start with left side:
\n" ); document.write( "(sin3x)/(sinxcosx)
\n" ); document.write( "=sin(2x+x)/(sinxcosx)
\n" ); document.write( "=(sin2xcosx+cos2xsinx)/(sinxcosx)=(2sinxcosxcosx+cos2xsinx)/(sinxcosx)
\n" ); document.write( "=2cosx+[(cos2xsinx)/(sinxcosx)]=2cosx+cos2x/cosx=2cosx+[(cos^2x-sin^2x)/cosx]
\n" ); document.write( "=2cosx+cosx-(sin^2x)/cosx)
\n" ); document.write( "=2cosx+cosx-1+cos^2x)/cosx)
\n" ); document.write( "=2cosx+cosx-1/cosx+cosx
\n" ); document.write( "=4cosx-1/cosx
\n" ); document.write( "=4cosx-secx
\n" ); document.write( "verified:
\n" ); document.write( "left side=right side\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
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