document.write( "Question 56747: I having trouble solving this equation
\n" ); document.write( "log (x+3)=1-log x
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Algebra.Com's Answer #38507 by funmath(2933)\"\" \"About 
You can put this solution on YOUR website!
The rules we are going to use are:
\n" ); document.write( "\"highlight%28log%28a%29%2Blog%28b%29=log%28a%2Ab%29%29\"
\n" ); document.write( "\"highlight%28log%28a%29=m%29\"==>>\"highlight%2810%5Em=a%29\"
\n" ); document.write( "\"log%28%28x%2B3%29%29=1-log%28%28x%29%29\"
\n" ); document.write( "\"log%28%28x%29%29%2Blog%28%28x%2B3%29%29=1-log%28%28x%29%29%2Blog%28%28x%29%29\"
\n" ); document.write( "\"log%28%28x%29%29%2Blog%28%28x%2B3%29%29=1\"
\n" ); document.write( "\"log%28x%28x%2B3%29%29=1\"
\n" ); document.write( "\"10%5E1=x%28x%2B3%29\"
\n" ); document.write( "\"10=x%5E2%2B3x\"
\n" ); document.write( "\"-10%2B10=x%5E2%2B3x-10\"
\n" ); document.write( "\"0=x%5E2%2B3x-10\" Factor:
\n" ); document.write( "0=(x__)(x___)
\n" ); document.write( "We need to fill the blanks with two integers that multiply to give us:-10, but add to give us:+3
\n" ); document.write( "5*(-2)=-10 and 5-2=+3
\n" ); document.write( "0=(x+5)(x-2)
\n" ); document.write( "x+5=0 and x-2=0
\n" ); document.write( "x=-5 and x=2
\n" ); document.write( "We have to check for extraneous solutions:
\n" ); document.write( "\"log%28-5%2B3%29=1-log%28-5%29\" x=-5 is extraneous, because we can't take the log of a negative number.
\n" ); document.write( "\"log%282%2B3%29=1-log%282%29\"
\n" ); document.write( "\"log%285%29=1-log%282%29\"
\n" ); document.write( "\".6989700043=.698700043\"
\n" ); document.write( "x=2 is a solution.
\n" ); document.write( "Happy Calculating!!!
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