document.write( "Question 611503: Solve the equation 49^(3x+1)=7^(2x-5)
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document.write( "Solve the equation log8(3x-1)=log8(x+4)
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document.write( "Solve the equation log6(x)=(1/4)log6(16)+(1/3)log6(64)
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document.write( "Find the antilogarithm of 1.5
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document.write( "Solve the equation ln(x)=5
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document.write( "Solve the equation 2^(2x+3)=3^(3x) \n" );
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Algebra.Com's Answer #384991 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Solve the equation \n" ); document.write( "49^(3x+1)=7^(2x-5) \n" ); document.write( "7^2(3x+1)=7^(x-5) \n" ); document.write( "7^(6x+2)=7^(x-5) \n" ); document.write( "6x+2=x-5 \n" ); document.write( "5x=-7 \n" ); document.write( "x=-7/5 \n" ); document.write( ".. \n" ); document.write( "Solve the equation log8(3x-1)=log8(x+4) \n" ); document.write( "3x-1=x+4 \n" ); document.write( "2x=5 \n" ); document.write( "x=5/2 \n" ); document.write( ".. \n" ); document.write( "Solve the equation \n" ); document.write( "log6(x)=(1/4)log6(16)+(1/3)log6(64) \n" ); document.write( "=log6(16)^(1/4)+log6(64)^1/3) \n" ); document.write( "log6(x)=log6(2)+log6(4) \n" ); document.write( "log6(x)-log6(2)-log6(4)=0 \n" ); document.write( "log6(x)-(log6(2)+log6(4))=0 \n" ); document.write( "place under single log \n" ); document.write( "log6[x/2*4]=0 \n" ); document.write( "convert to exponential form \n" ); document.write( "6^0=x/8=1 \n" ); document.write( "x=8 \n" ); document.write( ".. \n" ); document.write( "Find the \n" ); document.write( "antilogarithm of 1.5=10^1.5≈31.62 \n" ); document.write( ".. \n" ); document.write( "Solve the equation \n" ); document.write( "ln(x)=5 \n" ); document.write( "x=e^5≈148.41 \n" ); document.write( ".. \n" ); document.write( "Solve the equation \n" ); document.write( "2^(2x+3)=3^(3x) \n" ); document.write( "(2x+3)log2=(3x)log3 \n" ); document.write( "(2x+3)/3x=log3/log2≈1.585 \n" ); document.write( "2x+3=3x(1.585)=4.755x \n" ); document.write( "2.755x=3 \n" ); document.write( "x=3/2.755≈1.089 \n" ); document.write( " \n" ); document.write( " |