document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=611513>Question 611513</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am lost on this equation solution. I got the answer from the answer sheet but still  can't figure out how to get there.<BR>\n" );
document.write( " x/3 + y/6 = 1<BR>\n" );
document.write( " x/2 - y/4 = 0<BR>\n" );
document.write( "answer is  3/2, 3<BR>\n" );
document.write( "How? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #384982 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=384982\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Multiply first equation by 6 and second equation by 4 (this clears the fractions)\r<BR>\n" );
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document.write( "2x + y = 6<BR>\n" );
document.write( "2x - y = 0\r<BR>\n" );
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document.write( "Add both equations together to clear the y terms\r<BR>\n" );
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document.write( "4x = 6 --> x = 3/2\r<BR>\n" );
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document.write( "Replace x into either equation to obtain y = 3. </SPAN>\n" );
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