document.write( "Question 611416: your rectangular ad is 5 inches long its width is 2 inches shorter than the lenth what is the area of the ad \n" ); document.write( "
Algebra.Com's Answer #384956 by radh(108)\"\" \"About 
You can put this solution on YOUR website!
We know that to find the area of the rectangle, you use \"l%2Aw=a\". But this is a word problem, we don't have measurements put out for us that easily. Let's write this in a mathematical notation.
\n" ); document.write( "Your rectangular ad is 5 inches long (l=5). Its width is 2 inches shorter than the length (l-2).
\n" ); document.write( "Since we know that l = 5, we can plug that in to get the width. \"5-2=3\".
\n" ); document.write( "So, the length is 5 and the width is 3. \"3%2A5=15\"
\n" ); document.write( "The area of the rectangle is 15. :)
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