document.write( "Question 611378: how do I rewrite the quadratic equation x^2+6x-8 in vertex form? \n" ); document.write( "

Algebra.Com's Answer #384937 by solver91311(24713) $\"\"$ $\"About$

You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "What equation? Your quadratic trinomial isn't equal to anything, so you don't have an equation. Quadratic equation is the wrong terminology anyway. You want to talk about a quadratic function if you want to convert to vertex form.\r
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\n" ); document.write( "\n" ); document.write( "Try this:\r
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\n" ); document.write( "\n" ); document.write( "Now, complete the square on the right and then collect terms to result in a function that has the following pattern:\r
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\r
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\n" ); document.write( "\n" ); document.write( "which is a parabola with a vertical axis of symmetry and a vertex of (h,k). The parabola opens upward if

\ 0\">, downward otherwise.

is the distance from the vertex to the focus of the parabola and

is the distance from the vertex to the directrix.\r
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\n" ); document.write( "\n" ); document.write( "John
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\n" ); document.write( "My calculator said it, I believe it, that settles it
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$\"The$

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