document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=611350>Question 611350</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 85 grams of radioactive material will decay at a rate of 45% per day. How many grams will be left after 6 days? Round to the nearest hundredth.\r<BR>\n" );
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document.write( "This has to do with scientific notation </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #384912 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=384912\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  85 grams of radioactive material will decay at a rate of 45% per day. How many grams will be left after 6 days? Round to the nearest hundredth. <BR>\n" );
document.write( "This has to do with scientific notation<BR>\n" );
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document.write( "If 45% decays, 55% remains after each year.<BR>\n" );
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document.write( "A(t) = x*(0.55)^t<BR>\n" );
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document.write( "A(6) = 85*(0.55)^6 <BR>\n" );
document.write( "= 0.02353 <BR>\n" );
document.write( "= 2.353x10^-2 grams<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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