document.write( "Question 611212: Problem: One card is drawn from a standard deck of cards and then a second card is drawn, find the probability of drawing a king and then another face card (King, Queen, or Jack)If:\r
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document.write( "A) The first card is replaced before the second is drawn\r
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document.write( "B) The first card is set aside and not replaced in the deck before the second card is drawn.\r
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document.write( "I know we are talking about permutation and commutation. I believe this is a commutation problem, but once they throw probability in their, I get confused on how to set up the problems. If you could walk me through the problem so I can show my work and get a better understanding that would be great. \n" );
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Algebra.Com's Answer #384884 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Problem: One card is drawn from a standard deck of cards and then a second card is drawn, find the probability of drawing a king and then another face card (King, Queen, or Jack) \n" ); document.write( "------ \n" ); document.write( "Keep in mind the basic idea of probability: \n" ); document.write( "P(success) = # of ways to succeed/(# of possible outcomes) \n" ); document.write( "--- \n" ); document.write( "Note: Combinations and Permutations are simple 2 ways to \n" ); document.write( "help you count the # of successes and the # of possible \n" ); document.write( "outcomes. \n" ); document.write( "==========================\r \n" ); document.write( "\n" ); document.write( "If: \n" ); document.write( "A) The first card is replaced before the second is drawn \n" ); document.write( "# of ways to draw a King: 4 \n" ); document.write( "# of possible outcomes: 52 \n" ); document.write( "--- \n" ); document.write( "P(draw a King) = 4/52 = 1/13 \n" ); document.write( "P(draw a King twice with replacement) = (1/13)^2 = 1/169 \n" ); document.write( "========================================================== \n" ); document.write( " \n" ); document.write( "B) The first card is set aside and not replaced in the deck before the second card is drawn. \n" ); document.write( "P(draw 2 Kings without replacement) = (4/52)(3/51) = 12/2652 = 1/221 \n" ); document.write( "-- \n" ); document.write( "You could also get the B answer as follows: \n" ); document.write( "# of ways to draw 2 Kings: 4C2 = 6 \n" ); document.write( "# of ways to draw 2 cards randomly: 52C2 = 1326 \n" ); document.write( "P(draw 2 Kings without replacement) = 6/1326 = 1/221 \n" ); document.write( "======================================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |