document.write( "Question 611212: Problem: One card is drawn from a standard deck of cards and then a second card is drawn, find the probability of drawing a king and then another face card (King, Queen, or Jack)If:\r
\n" ); document.write( "\n" ); document.write( "A) The first card is replaced before the second is drawn\r
\n" ); document.write( "\n" ); document.write( "B) The first card is set aside and not replaced in the deck before the second card is drawn.\r
\n" ); document.write( "\n" ); document.write( "I know we are talking about permutation and commutation. I believe this is a commutation problem, but once they throw probability in their, I get confused on how to set up the problems. If you could walk me through the problem so I can show my work and get a better understanding that would be great.
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Algebra.Com's Answer #384884 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Problem: One card is drawn from a standard deck of cards and then a second card is drawn, find the probability of drawing a king and then another face card (King, Queen, or Jack)
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\n" ); document.write( "Keep in mind the basic idea of probability:
\n" ); document.write( "P(success) = # of ways to succeed/(# of possible outcomes)
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\n" ); document.write( "Note: Combinations and Permutations are simple 2 ways to
\n" ); document.write( "help you count the # of successes and the # of possible
\n" ); document.write( "outcomes.
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\n" ); document.write( "\n" ); document.write( "If:
\n" ); document.write( "A) The first card is replaced before the second is drawn
\n" ); document.write( "# of ways to draw a King: 4
\n" ); document.write( "# of possible outcomes: 52
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\n" ); document.write( "P(draw a King) = 4/52 = 1/13
\n" ); document.write( "P(draw a King twice with replacement) = (1/13)^2 = 1/169
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\n" ); document.write( "B) The first card is set aside and not replaced in the deck before the second card is drawn.
\n" ); document.write( "P(draw 2 Kings without replacement) = (4/52)(3/51) = 12/2652 = 1/221
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\n" ); document.write( "You could also get the B answer as follows:
\n" ); document.write( "# of ways to draw 2 Kings: 4C2 = 6
\n" ); document.write( "# of ways to draw 2 cards randomly: 52C2 = 1326
\n" ); document.write( "P(draw 2 Kings without replacement) = 6/1326 = 1/221
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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