document.write( "Question 611078: find the length and the width of a rectangle whose perimeter is 18 ft whose area is 20 square feet \n" ); document.write( "
Algebra.Com's Answer #384843 by ankor@dixie-net.com(22740)\"\" \"About 
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find the length and the width of a rectangle whose perimeter is 18 ft
\n" ); document.write( "2L + 2W = 18
\n" ); document.write( "simplify, divide by 2
\n" ); document.write( "L + W = 9
\n" ); document.write( "L = (9-W)
\n" ); document.write( ":
\n" ); document.write( "whose area is 20 square feet
\n" ); document.write( "L*W = 20
\n" ); document.write( "Replace L with (9-W)
\n" ); document.write( "W(9-W) = 20
\n" ); document.write( "-W^2 + 9W - 20 = 0
\n" ); document.write( "Multiply by -1, easier to factor
\n" ); document.write( "W^2 - 9W + 20
\n" ); document.write( "Factors to
\n" ); document.write( "(W-4)(W-5) = 0
\n" ); document.write( "Two solutions
\n" ); document.write( "W = 4 ft is width, then 5 ft is the Length
\n" ); document.write( "and
\n" ); document.write( "W = 5 ft is the width, then 4 ft is the Length
\n" ); document.write( ": \n" ); document.write( "
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