document.write( "Question 611001: Find to the nearest degree, all values of theta in the interval 0 degrees is < or equal to theta which is < 180 degrees, that satisfy the equation:\r
\n" );
document.write( "\n" );
document.write( "3tan^2 theta+(1/cot theta)= 2 \n" );
document.write( "
Algebra.Com's Answer #384783 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Find to the nearest degree, all values of theta in the interval 0 degrees is < or equal to theta which is < 180 degrees, that satisfy the equation: \n" ); document.write( "3tan^2 theta+(1/cot theta)= 2 \n" ); document.write( "** \n" ); document.write( "3tan^2x+(1/cotx)=2 \n" ); document.write( "3tan^2x+tanx-2=0 \n" ); document.write( "(3tanx-2)(tanx+1)=0 \n" ); document.write( ".. \n" ); document.write( "3tanx-2=0 \n" ); document.write( "tanx=2/3 \n" ); document.write( "x≈37º and 214º (in quadrants I and III where tan>0)) \n" ); document.write( ".. \n" ); document.write( "tanx+1=0 \n" ); document.write( "tanx=-1 \n" ); document.write( "x=135º and 315º (in quadrants II and IVI where tan<0)) \n" ); document.write( " |