document.write( "Question 611001: Find to the nearest degree, all values of theta in the interval 0 degrees is < or equal to theta which is < 180 degrees, that satisfy the equation:\r
\n" ); document.write( "\n" ); document.write( "3tan^2 theta+(1/cot theta)= 2
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Algebra.Com's Answer #384783 by lwsshak3(11628)\"\" \"About 
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Find to the nearest degree, all values of theta in the interval 0 degrees is < or equal to theta which is < 180 degrees, that satisfy the equation:
\n" ); document.write( "3tan^2 theta+(1/cot theta)= 2
\n" ); document.write( "**
\n" ); document.write( "3tan^2x+(1/cotx)=2
\n" ); document.write( "3tan^2x+tanx-2=0
\n" ); document.write( "(3tanx-2)(tanx+1)=0
\n" ); document.write( "..
\n" ); document.write( "3tanx-2=0
\n" ); document.write( "tanx=2/3
\n" ); document.write( "x≈37º and 214º (in quadrants I and III where tan>0))
\n" ); document.write( "..
\n" ); document.write( "tanx+1=0
\n" ); document.write( "tanx=-1
\n" ); document.write( "x=135º and 315º (in quadrants II and IVI where tan<0))
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