document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=610955>Question 610955</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Three fair dice are rolled. Given that none of them turned up a \"1\" compute the probability that none of them turned up a \"3\". </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #384688 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=384688\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Every die roll turned out to be a 2,3,4,5, or 6 with equal probability. Therefore the probability of obtaining a 3 given that a 1 wasn't rolled is 1/5. (1/5)^3 = 1/125. </SPAN>\n" );
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