document.write( "Question 610958: The sum of 2 numbers is 47 and their difference is 13. What are the numbers ? \n" ); document.write( "
Algebra.Com's Answer #384683 by radh(108)\"\" \"About 
You can put this solution on YOUR website!
Let's write a system of equations to solve this problem:
\n" ); document.write( "x+y=47
\n" ); document.write( "x-y=13.
\n" ); document.write( "

Let's solve using Cramer's Rule.\r
\n" ); document.write( "\n" ); document.write( "

\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
Solved by pluggable solver: Using Cramer's Rule to Solve Systems with 2 variables

\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"system%281%2Ax%2B1%2Ay=47%2C1%2Ax%2B-1%2Ay=13%29\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " First let \"A=%28matrix%282%2C2%2C1%2C1%2C1%2C-1%29%29\". This is the matrix formed by the coefficients of the given system of equations.
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Take note that the right hand values of the system are \"47\" and \"13\" which are highlighted here:
\n" ); document.write( " \"system%281%2Ax%2B1%2Ay=highlight%2847%29%2C1%2Ax%2B-1%2Ay=highlight%2813%29%29\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " These values are important as they will be used to replace the columns of the matrix A.
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Now let's calculate the the determinant of the matrix A to get \"abs%28A%29=%281%29%28-1%29-%281%29%281%29=-2\". Remember that the determinant of the 2x2 matrix \"A=%28matrix%282%2C2%2Ca%2Cb%2Cc%2Cd%29%29\" is \"abs%28A%29=ad-bc\". If you need help with calculating the determinant of any two by two matrices, then check out this solver.
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Notation note: \"abs%28A%29\" denotes the determinant of the matrix A.
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " ---------------------------------------------------------
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Now replace the first column of A (that corresponds to the variable 'x') with the values that form the right hand side of the system of equations. We will denote this new matrix \"A%5Bx%5D\" (since we're replacing the 'x' column so to speak).
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"A%5Bx%5D=%28matrix%282%2C2%2Chighlight%2847%29%2C1%2Chighlight%2813%29%2C-1%29%29\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Now compute the determinant of \"A%5Bx%5D\" to get \"abs%28A%5Bx%5D%29=%2847%29%28-1%29-%281%29%2813%29=-60\". Once again, remember that the determinant of the 2x2 matrix \"A=%28matrix%282%2C2%2Ca%2Cb%2Cc%2Cd%29%29\" is \"abs%28A%29=ad-bc\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " To find the first solution, simply divide the determinant of \"A%5Bx%5D\" by the determinant of \"A\" to get: \"x=%28abs%28A%5Bx%5D%29%29%2F%28abs%28A%29%29=%28-60%29%2F%28-2%29=30\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " So the first solution is \"x=30\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " ---------------------------------------------------------
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " We'll follow the same basic idea to find the other solution. Let's reset by letting \"A=%28matrix%282%2C2%2C1%2C1%2C1%2C-1%29%29\" again (this is the coefficient matrix).
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Now replace the second column of A (that corresponds to the variable 'y') with the values that form the right hand side of the system of equations. We will denote this new matrix \"A%5By%5D\" (since we're replacing the 'y' column in a way).
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"A%5Bx%5D=%28matrix%282%2C2%2C1%2Chighlight%2847%29%2C1%2Chighlight%2813%29%29%29\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Now compute the determinant of \"A%5By%5D\" to get \"abs%28A%5By%5D%29=%281%29%2813%29-%2847%29%281%29=-34\".
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " To find the second solution, divide the determinant of \"A%5By%5D\" by the determinant of \"A\" to get: \"y=%28abs%28A%5By%5D%29%29%2F%28abs%28A%29%29=%28-34%29%2F%28-2%29=17\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " So the second solution is \"y=17\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " ====================================================================================
\n" ); document.write( "
\n" ); document.write( " Final Answer:
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " So the solutions are \"x=30\" and \"y=17\" giving the ordered pair (30, 17)
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Once again, Cramer's Rule is dependent on determinants. Take a look at this 2x2 Determinant Solver if you need more practice with determinants.
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \n" ); document.write( "

\n" );