document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=610673>Question 610673</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help!\r<BR>\n" );
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document.write( "The sum of three numbers is 29. The greatest number is four times the smallest number. the remaining number is 1 more than twice the smallest number. Find the three numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #384612 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=384612\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Three numbers: a, b, c; (a is the largest)<BR>\n" );
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document.write( "Write an equation for each statement<BR>\n" );
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document.write( "The sum of three numbers is 29.<BR>\n" );
document.write( "a + b + c = 29<BR>\n" );
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document.write( "The greatest number is four times the smallest number.<BR>\n" );
document.write( "a = 4c<BR>\n" );
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document.write( "the remaining number is 1 more than twice the smallest number.<BR>\n" );
document.write( "b = 2c + 1<BR>\n" );
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document.write( "Find the three numbers.<BR>\n" );
document.write( "using the 1st equation, replace a with 4c, replace b with (2c+1)<BR>\n" );
document.write( "4c + (2c+1) + c = 29<BR>\n" );
document.write( "7c + 1 = 29<BR>\n" );
document.write( "7c = 29-1<BR>\n" );
document.write( "c = 28/7<BR>\n" );
document.write( "c = 4<BR>\n" );
document.write( "then<BR>\n" );
document.write( "a = 4(4) = 16<BR>\n" );
document.write( "b = 2(4) + 1 = 9<BR>\n" );
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document.write( "16, 9, 4 are the three numbers<BR>\n" );
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document.write( "You can check the solutions by finding their sum </SPAN>\n" );
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