document.write( "Question 610806: Determine whether the argument is valid or not.\r
\n" ); document.write( "\n" ); document.write( "pV~q
\n" ); document.write( "p
\n" ); document.write( "_____
\n" ); document.write( "∴ ~q
\n" ); document.write( "

Algebra.Com's Answer #384590 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
This is not a valid argument. You would need ~p as a premise to deduce ~q as the conclusion.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Further proof is in the table\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\r\n" );
document.write( "p    q     ~q      p V ~q\r\n" );
document.write( "----------------------------\r\n" );
document.write( "T    T      F        T\r\n" );
document.write( "T    F      T        T\r\n" );
document.write( "F    T      F        F\r\n" );
document.write( "F    F      T        T\r\n" );
document.write( "
\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Notice how on the first line that every premise is true BUT the conclusion (~q) is false. This shows us that the argument is NOT valid.
\n" ); document.write( "
\n" );