document.write( "Question 610806: Determine whether the argument is valid or not.\r
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document.write( "pV~q
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document.write( "p
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document.write( "_____
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document.write( "∴ ~q \n" );
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Algebra.Com's Answer #384590 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! This is not a valid argument. You would need ~p as a premise to deduce ~q as the conclusion.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Further proof is in the table\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "p q ~q p V ~q\r\n" ); document.write( "----------------------------\r\n" ); document.write( "T T F T\r\n" ); document.write( "T F T T\r\n" ); document.write( "F T F F\r\n" ); document.write( "F F T T\r\n" ); document.write( "\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Notice how on the first line that every premise is true BUT the conclusion (~q) is false. This shows us that the argument is NOT valid. \n" ); document.write( " |