document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=56685>Question 56685</A>: <I><SPAN STYLE=\"word-break: break-all;\"> hai<BR>\n" );
document.write( " i am doing B.Sc(maths) Ist year at madurai kamaraj university in correspondence.\r<BR>\n" );
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document.write( "this question is from trigonometry, complex numbers\r<BR>\n" );
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document.write( "find the modulus and amplidude form of (1-i)(1-2i)/(1+3i) <BR>\n" );
document.write( "i have tried this one\r<BR>\n" );
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document.write( "(1-i)(1-2i)/(1+3i)   =  (1-i)(1-2i)(1+3i)/(1-3i)(1+3i)(multiplyingnumerator & dinominator by the conjugate)  <BR>\n" );
document.write( "                     =(8+6i^3)/10<BR>\n" );
document.write( "(1-i)(1-2i)/(1+3i)   =(4-3i)/5\r<BR>\n" );
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document.write( "                    r=square root(x^2+y^2)<BR>\n" );
document.write( "                     =square root ((4/5)^2+(-3/5)^2)<BR>\n" );
document.write( "                    r=square root (1)\r<BR>\n" );
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document.write( "                     cos theta=x/r<BR>\n" );
document.write( "                              =4/5 square root (1)<BR>\n" );
document.write( "                     sin theta=y/r<BR>\n" );
document.write( "                              =-3/5 square root(1)<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #38458 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=38458\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "SEE MY COMMENTS BELOW<BR>\n" );
document.write( "hai<BR>\n" );
document.write( "i am doing B.Sc(maths) Ist year at madurai kamaraj university in correspondence. <BR>\n" );
document.write( "this question is from trigonometry, complex numbers <BR>\n" );
document.write( "find the modulus and amplidude form of (1-i)(1-2i)/(1+3i) <BR>\n" );
document.write( "i have tried this one <BR>\n" );
document.write( "(1-i)(1-2i)/(1+3i) = (1-i)(1-2i)(1+3i)/(1-3i)(1+3i)(multiplyingnumerator & dinominator by the conjugate) ......GOOD<BR>\n" );
document.write( "=(8+6i^3)/10.........................VERY GOOD<BR>\n" );
document.write( "(1-i)(1-2i)/(1+3i) =(4-3i)/5 ..OK..BUT SIMPLER IS 8+6I^3=8+6I*I^2=8-6I=2(4-3I)<BR>\n" );
document.write( "r=square root(x^2+y^2)...............GOOD<BR>\n" );
document.write( "=square root ((4/5)^2+(-3/5)^2).................GOOD<BR>\n" );
document.write( "r=square root (1) =OK.....PUT IT AS = 1<BR>\n" );
document.write( "cos theta=x/r...NO WHY?<BR>\n" );
document.write( "PUT TAN THETA = -3/4 AND THETA = ARC TAN(-3/4) IS THE AMPLITUDE<BR>\n" );
document.write( "WELL ONE KEEP IT UP..YOU NEED JUST A LITTLE BRUSHING UP..<BR>\n" );
document.write( "=4/5 square root (1)<BR>\n" );
document.write( "sin theta=y/r<BR>\n" );
document.write( "=-3/5 square root(1)\r<BR>\n" );
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