document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=610799>Question 610799</A>: <I><SPAN STYLE=\"word-break: break-all;\"> log8 x=3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #384579 by </B><A HREF=/tutors/aboutme.mpl?userid=fcabanski><B>fcabanski(1391)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fcabanski><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=384579\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The definition of logarithms is that log(base y)x = a is equivalent to y^a = x. <P><BR>\n" );
document.write( "In this problem 8^3 = x, so x = 512.<P><BR>\n" );
document.write( "Contact me for private tutoring or direct, one on one problem solving.  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );