document.write( "Question 610717: Suppose we want to determine the (binomial) probability (p) of getting 0 (zero) heads in 5 flips of a 2-sided coin. Using the table [(n/x) * p^x * q^(n-x)]
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Algebra.Com's Answer #384549 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi, 
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document.write( "Note: Use of [(nCx) * p^x * q^(n-x)] below:
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document.write( "P(0 heads in 5 flips)
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document.write( "Note: The probability of x successes in n trials is: 
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document.write( " where p and q are the probabilities of success and failure respectively. 
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document.write( "In this case  & q(tails) = 1/2 or .5
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document.write( "nCx =    and 
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document.write( "P = 5C0(.5)^0(.5)^5 = 1(.5)^0(.5)^5 =  \n" );
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