document.write( "Question 610741: a father is twice as old as his son and the sum of their ages is 90 years. Find their present ages ? \n" ); document.write( "

Algebra.Com's Answer #384548 by radh(108) $\"\"$ $\"About$

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Let's map this out mathematically. We'll use x for the age.
\n" ); document.write( "A father is twice (2x) as old as his son and the sum of their ages is 90 years.
\n" ); document.write( " $\"2x%2Bx=90\"$
\n" ); document.write( "There's a similar x in there, right? So we can simplify into: $\"3x=90\"$ and then isolate the variable by dividing the 3 out to get $\"x=30\"$ .\r
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Going back to the problem, we know that the father is 2x. We know x is 30 now, so $\"2%2830%29=60\"$ . The son is just x, so he is thirty.\r
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Father = 60 years
\n" ); document.write( "Son = 30 years \n" ); document.write( "

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