document.write( "Question 610650: What is the equation of the line which goes through (6,2) that is parallel to y+x-3=0 \n" ); document.write( "

Algebra.Com's Answer #384509 by Maths68(1474) $\"\"$ $\"About$

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Equation of the line slope-intercept form
\n" ); document.write( "y=mx+b
\n" ); document.write( "Given
\n" ); document.write( "Equation of the Given line
\n" ); document.write( "y+x-3=0
\n" ); document.write( "y=-x+3
\n" ); document.write( "Compare with the equation of line slope-intercept form
\n" ); document.write( "Slope of the given = m = -1
\n" ); document.write( "Since lines are parallel their slope will be same
\n" ); document.write( "Slope of the required line = m = -1
\n" ); document.write( "Point (6, 2)
\n" ); document.write( "We have a point and slope we can get easily the require line equation.
\n" ); document.write( "Use Equation of the line point-slope form
\n" ); document.write( "m = y2-y1/x2-x1
\n" ); document.write( "Put the values in above equation, we have
\n" ); document.write( "-1=(y-2)/(x-6)
\n" ); document.write( "-(x-6)=y-2
\n" ); document.write( "-x+6=y-2
\n" ); document.write( "y-2=-x+6
\n" ); document.write( "y=-x+6+2
\n" ); document.write( "y=-x+8
\n" ); document.write( "Above equation is the equation of the required line\r
\n" ); document.write( "\n" ); document.write( "Graph
\n" ); document.write( "========
\n" ); document.write( "y=-x+3 (Red line)
\n" ); document.write( "y=-x+8 (Green line)\r
\n" ); document.write( "\n" ); document.write( " $\"graph%28500%2C500%2C-10%2C10%2C-10%2C10%2C-x%2B3%2C-x%2B8%29\"$
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