document.write( "Question 610628: If a vehicle is traveling at 67 mph and another vehicle wants to catch the vehicle traveling at 67 mph within one mile, how fast would the 2nd vehicle have to travel in order to catch the 1st vehicle if the 1st vehicle was 1/2 mile away at the time the 2nd vehicle began excelleration? \n" ); document.write( "

Algebra.Com's Answer #384486 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
I think the question should be phrased as:
\n" ); document.write( "\"What is the average speed of the 2nd vehicle in order to catch the 1st?\"
\n" ); document.write( "--------------
\n" ); document.write( "The head start of the 1st vehicle is $\"+.5+\"$ mi
\n" ); document.write( "Start a stop watch when the 2nd vehicle leaves
\n" ); document.write( " $\"+1+\"$ mi = the distance that the 2nd vehicle has
\n" ); document.write( "to travel until it catches the 1st one.
\n" ); document.write( "Let $\"+t+\"$ = the time in hours on the stopwatch from when
\n" ); document.write( "the 2nd vehicle leaves until it catches the 1st one.
\n" ); document.write( "Let $\"+r+\"$ = the average speed of the 2nd vehicle
\n" ); document.write( "--------------
\n" ); document.write( "Equation for 1st vehicle:
\n" ); document.write( "(1) $\"+1+-+.5+=+67t+\"$
\n" ); document.write( "Equation for 2nd vehicle:
\n" ); document.write( "(2) $\"+1+=+r%2At+\"$
\n" ); document.write( "-------------
\n" ); document.write( "(1) $\"+.5+=+67t+\"$
\n" ); document.write( "(1) $\"+t+=+.5%2F67+\"$
\n" ); document.write( "(1) $\"+t+=+1%2F134+\"$
\n" ); document.write( "(1) $\"+1%2Ft+=+134+\"$
\n" ); document.write( "and
\n" ); document.write( "(2) $\"+1+=+r%2At+\"$
\n" ); document.write( "(2) $\"+r+=+1%2Ft+\"$
\n" ); document.write( "(2) $\"+r+=+134+\"$
\n" ); document.write( "--------------
\n" ); document.write( "The average speed of the 2nd vehicle must be at least 134 mi/hr
\n" ); document.write( " \n" ); document.write( "

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