document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=610543>Question 610543</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you prove that 1-cos2x=2sin^2x? I don't even know how to start this problem. Please help =) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #384458 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=384458\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> cos(2x) = cos^2(x) - sin^2(x)\r<BR>\n" );
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document.write( "1 - [cos^2(x) - sin^2(x)] = 2 sin^2(x)\r<BR>\n" );
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document.write( "1 - cos^2(x) + sin^2(x) = 2 sin^2(x)\r<BR>\n" );
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document.write( "1 - cos^2(x) = sin^2(x)\r<BR>\n" );
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document.write( "1 = sin^2(x) + cos^2(x)<BR>\n" );
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