document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=610525>Question 610525</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rectangle has the dimensions 1080/x^2-5x+6 by x-2/x. If the area is 20 units^2, find the value(s) for x.\r<BR>\n" );
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document.write( "I got 1060/x(x-3) but I don't think that is right. Help would be greatly appreciated!  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #384446 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=384446\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A rectangle has the dimensions 1080/x^2-5x+6 by x-2/x. If the area is 20 units^2, find the value(s) for x. <BR>\n" );
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document.write( "[1080/x^2-5x+6] * [x-2/x] = 20<BR>\n" );
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document.write( "[1080/(x=3)(x-2)] * [x-2/x] = 20<BR>\n" );
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document.write( "[1080/(x-3)] * [1/x] = 20<BR>\n" );
document.write( "Multiply thru by x(x-3) to get:<BR>\n" );
document.write( "1080 = 20x(x-3)<BR>\n" );
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document.write( "20x^2-60x-1080 = 0<BR>\n" );
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document.write( "x^2 - 3x - 54 = 0<BR>\n" );
document.write( "(x-9)(x+6) = 0<BR>\n" );
document.write( "x = 9 or x = -6<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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