document.write( "Question 610415: how do I solve the equation 16+4x=2y and 3x+5y=27 \n" ); document.write( "
Algebra.Com's Answer #384375 by Alan3354(69443)\"\" \"About 
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how do I solve the equation 16+4x=2y and 3x+5y=27
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\n" ); document.write( "That's actually 2 equations, a system of equations
\n" ); document.write( "16+4x=2y Eqn 1
\n" ); document.write( "3x+5y=27 Eqn 2
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\n" ); document.write( "There's more than one way, but substitution works well for these.
\n" ); document.write( "16+4x=2y Eqn 1
\n" ); document.write( "8 + 2x = y Eqn 1 * 1/2
\n" ); document.write( "Sub for y in Eqn 2
\n" ); document.write( "3x+5y=27
\n" ); document.write( "3x + 5(8+2x) = 27
\n" ); document.write( "Solve for x. Then sub and solve for y
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