document.write( "Question 610379: Determine whether each of the distributions given below represents a probability distribution. Justify your answer.
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document.write( "(A)
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document.write( " x 1 2 3 4
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document.write( "P(x)3/5 12/25 3/25 0
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document.write( "(B)
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document.write( " x 3 6 8
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document.write( "P(x)0.15 3/5 0.25
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document.write( "(C)
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document.write( " x 20 35 40 50
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document.write( "P(x)0.45 0.25 1/4 0.05
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document.write( " each is lined above each other.
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document.write( "example in (c)
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document.write( "20 is directly above 0.45, 35 is directly above 0.25, 40 is directly above 1/4 etc.
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Algebra.Com's Answer #384354 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! (A) \n" ); document.write( "x 1 2 3 4\r \n" ); document.write( "\n" ); document.write( "P(x)3/5 12/25 3/25 0 \n" ); document.write( "No, because the sum of the P(x)'s is greater than one. \n" ); document.write( "========================================\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(B) \n" ); document.write( "x 3 6 8\r \n" ); document.write( "\n" ); document.write( "P(x)0.15 3/5 0.25 \n" ); document.write( "Yes beause sum of P(x)'s = 1 and each P(x) is between 0 and 1 \n" ); document.write( "=========================================== \r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(C) \n" ); document.write( "x 20 35 40 50\r \n" ); document.write( "\n" ); document.write( "P(x)0.45 0.25 1/4 0.05 \n" ); document.write( "Yes for same reason as for \"B\" \n" ); document.write( "================================ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |