document.write( "Question 610321: what do the graphs for y=1/12(x)^2 and x+-1/4(y)^2 look like
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Algebra.Com's Answer #384342 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi,
\n" ); document.write( "what do the graphs for y=1/12(x)^2 and x = -1/4(y)^2 look like ||Assume the + was an = sign
\n" ); document.write( "the vertex form of a parabola opening up or down, \"y=a%28x-h%29%5E2+%2Bk\" where(h,k) is the vertex.The standard form is \"%28x+-h%29%5E2+=+4p%28y+-k%29\", where the focus is (h,k + p)
\n" ); document.write( "\"y=%281%2F12%29%28x%29%5E2+\" opens Upward as a = 1/12 > 0 Green
\n" ); document.write( "the vertex form of a parabola opening right or left, \"x=a%28y-k%29%5E2+%2Bh\" where(h,k) is the vertex.The standard form is \"%28y+-k%29%5E2+=+4p%28x+-h%29\", where the focus is (h +p,k )
\n" ); document.write( "\"x+=+%28-1%2F4%29%28y%29%5E2\" opens to the LEFT as a = -1/4 < 0
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