document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=610352>Question 610352</A>: <I><SPAN STYLE=\"word-break: break-all;\"> one number exceeds another by 5. if the larger is increased by 5 and the smaller is decreased by 8, the larger will be 12 less than twice the smaller. find the original. with solution please. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #384336 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=384336\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> one number exceeds another by 5. if the larger is increased by 5 and the smaller is decreased by 8, the larger will be 12 less than twice the smaller. find the original. with solution please.<BR>\n" );
document.write( "**<BR>\n" );
document.write( "let x=smaller number<BR>\n" );
document.write( "x+5=larger number<BR>\n" );
document.write( "increase larger number by 5=x+5+5<BR>\n" );
document.write( "Twice the smaller decreased by 8=2(x-8)<BR>\n" );
document.write( "x+5+5-12=2(x-8)<BR>\n" );
document.write( "x-2=2x-16<BR>\n" );
document.write( "x=14<BR>\n" );
document.write( "x+5=19<BR>\n" );
document.write( "ans<BR>\n" );
document.write( "smaller number=14<BR>\n" );
document.write( "larger number=19<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );