document.write( "Question 610303: Find the exact values of sin(2theta), and cos(2theta) if sin(theta)= -9/10 and theta is between 180 degrees and 270 degrees. \n" ); document.write( "
Algebra.Com's Answer #384330 by lwsshak3(11628)\"\" \"About 
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Find the exact values of sin(2theta), and cos(2theta) if sin(theta)= -9/10 and theta is between 180 degrees and 270 degrees.
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\n" ); document.write( "use x in place of theta.
\n" ); document.write( "sinx=-9/10=opposite side/hypotenuse (in quadrant III where sin is <0)
\n" ); document.write( "Adjacent side=√(10^2-9^2)=√(100-81)=√19
\n" ); document.write( "cosx=-√19/10 (in quadrant III where cos is also<0)
\n" ); document.write( "..
\n" ); document.write( "sin2x=2sinxcosx
\n" ); document.write( "=2*(-9/10)*(-√19/10)
\n" ); document.write( "=18√19/100
\n" ); document.write( "=(9√19)/50 (in quadrant II where sin>0)
\n" ); document.write( "..
\n" ); document.write( "cos2x=cos^2x-sin^2x
\n" ); document.write( "=(-√19/10)^2-(-9/10)^2
\n" ); document.write( "=19/100-81/100
\n" ); document.write( "=-62/100
\n" ); document.write( "=-31/50 (in quadrant II where cos<0)
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