document.write( "Question 610338: graph y>=sqrt3x+12 \n" ); document.write( "
Algebra.Com's Answer #384327 by flame8855(424)\"\" \"About 
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\"+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C++sqrt%283x%2B12%29+%29+\"\r
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\n" ); document.write( "\n" ); document.write( "the answer is the area above the curve
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