document.write( "Question 56594: In one year, Andrew earned the same interest from an investment at 8% as an investment at 12%. He had invested $1500 in the 8% than in the 12% account. How much did he invest in each account?\r
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Algebra.Com's Answer #38431 by ankor@dixie-net.com(22740)\"\" \"About 
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In one year, Andrew earned the same interest from an investment at 8% as an investment at 12%. He had invested $1500 more in the 8% than in the 12% account. How much did he invest in each account?
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\n" ); document.write( "Let x = amt invested at 12%
\n" ); document.write( "Then (x+1500) amt invested at 8%
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\n" ); document.write( "Since the interest amt from two investments are equal we can make an equation from that:
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\n" ); document.write( "12% interest = 8% interest
\n" ); document.write( ".12x = .08(x+1500)
\n" ); document.write( ".12x = .08x + 120
\n" ); document.write( ".12x - .08x = 120
\n" ); document.write( ".04x = 120
\n" ); document.write( "x = 120/.04
\n" ); document.write( "x = $3000 invested at 12 %
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\n" ); document.write( "Then 3000 + 1500 = $4500 invested at 8%
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\n" ); document.write( "Check to see if the interests are, in fact, equal:
\n" ); document.write( " .08(4500) = .12(3000)
\n" ); document.write( "360 = 360
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