document.write( "Question 56642: Find an equation of a line passing through (-1,1) and perpendicular to the line whose equation is given by 3x-2y=1. \n" ); document.write( "
Algebra.Com's Answer #38429 by funmath(2933)\"\" \"About 
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Find an equation of a line passing through (-1,1) and perpendicular to the line whose equation is given by 3x-2y=1.
\n" ); document.write( "First find the slope of the equation by putting it in slope intercept form:\"highlight%28y=mx%2Bb%29\", where m=slope and (0,b)=y-intercept:
\n" ); document.write( "\"3x-2y=1\"
\n" ); document.write( "\"-3x%2B3x-2y=-3x%2B1\"
\n" ); document.write( "\"-2y=-3x%2B1\"
\n" ); document.write( "\"-2y%2F-2=-3x%2F-2%2B1%2F-2\"
\n" ); document.write( "\"y=%283%2F2%29x-1%2F2\"
\n" ); document.write( "\"y=highlight%28%283%2F2%29%29x-1%2F2\", the slope,m=3/2.
\n" ); document.write( "Perpendicular equations have slopes that are negative reciprocals of each other, so flip the slope over and change its sign.
\n" ); document.write( "We need a line with a slope, m=-2/3 going through the point (x1,y1)=(-1,1).
\n" ); document.write( "We need to use the point slope formula \"highlight%28y-y1=m%28x-x1%29%29\".
\n" ); document.write( "\"y-1=%28-2%2F3%29%28x-%28-1%29%29\"
\n" ); document.write( "\"y-1=%28-2%2F3%29%28x%2B1%29\"
\n" ); document.write( "\"y-1=%28-2%2F3%29x-%282%2F3%29%281%29\"
\n" ); document.write( "\"y-1=%28-2%2F3%29x-2%2F3\"
\n" ); document.write( "\"y-1%2B1=%28-2%2F3%29x-2%2F3%2B1\"
\n" ); document.write( "\"y=%28-2%2F3%29x-2%2F3%2B3%2F3\"
\n" ); document.write( "\"y=%28-2%2F3%29x%2B%28-2%2B3%29%2F3\"
\n" ); document.write( "\"y=%28-2%2F3%29x%2B1%2F3\" <--Slope intercept form
\n" ); document.write( "\"3y=-2x%2B1\"
\n" ); document.write( "\"2x%2B3y=1\" <--Standard form
\n" ); document.write( "Happy Calculating!!!
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