document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=610256>Question 610256</A>: <I><SPAN STYLE=\"word-break: break-all;\"> right side completely factor<BR>\n" );
document.write( "-2x^2+76x+430 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #384257 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=384257\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> find factors of -860 which ad up to 76<BR>\n" );
document.write( "or better factor out the -2 first and find factors of -215 which add up to -38<BR>\n" );
document.write( "-2*(x^2-43x+5x-215)<BR>\n" );
document.write( "-2*(x*(x-43) +5*(x-43)<BR>\n" );
document.write( "-2 *(x+5)*(x-43) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );