document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=610246>Question 610246</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 300 gms of sugar solution contains 40% sugar. How much sugar should be added to make it 50% sugar solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #384251 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=384251\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = the number of grams of sugar to be added to the 300gm of 40% sugar solution.<BR>\n" );
document.write( "300(0.4)+x = (300+x)(0.5) Simplify.<BR>\n" );
document.write( "120+x = 150+0.5x Subtract 0.5x from both sides.<BR>\n" );
document.write( "120+0.5x = 150 Now subtract 120 from both sides.<BR>\n" );
document.write( "0.5x = 30 Multiply both sides by 2.<BR>\n" );
document.write( "x = 60<BR>\n" );
document.write( "Add 60 grams of sugar to the 300gm of 40% sugar solution to obtain 360gm of 50% sugar solution. </SPAN>\n" );
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