document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=610248>Question 610248</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Jerome started with 12/14 cups of flour. If he gave 2/6 to Jane and Nick gave him 6/10 then how many cups of flour did Jerome have in the end? Fraction must be in Simplest form\r<BR>\n" );
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document.write( "I figured it to be 76/60 or 1 4/15 is this right? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #384248 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=384248\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The question is not clear. Did he give 2/6(1/3) of a cup or 2/6 of what he had.<BR>\n" );
document.write( "The 6/10 is even more vague.  Why isn't 2/6 expressed in reduced form as 1/3 and the same with 6/10 for 3/5 and 12/14 as 6/7. <BR>\n" );
document.write( "Assuming 3/5 cup and 1/3 cup<BR>\n" );
document.write( "6/7-1/3+3/5\r<BR>\n" );
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document.write( " 90/105-35/105+63/105 \r<BR>\n" );
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document.write( " 118/105<BR>\n" );
document.write( "1 13/105<BR>\n" );
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