document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=610249>Question 610249</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a square and a rectangle have the same are. what is the numerical value of the rectangles perimeter? if the squares sides are x and the rectangle's length is 2x-3 and width is x-3. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #384246 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=384246\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x^2 = (2x-3)(x-3)\r<BR>\n" );
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document.write( "x^2 = 2x^2 - 6x - 3x + 9\r<BR>\n" );
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document.write( "0 = 2x^2 - 6x - 3x + 9 - x^2\r<BR>\n" );
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document.write( "0 = x^2 - 9x + 9\r<BR>\n" );
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document.write( "x^2 - 9x + 9 = 0\r<BR>\n" );
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document.write( "Now use the quadratic formula to solve for x\r<BR>\n" );
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document.write( "x = (-b+-sqrt(b^2-4ac))/(2a)\r<BR>\n" );
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document.write( "x = (-(-9)+-sqrt((-9)^2-4(1)(9)))/(2(1))\r<BR>\n" );
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document.write( "x = (9+-sqrt(81-(36)))/(2)\r<BR>\n" );
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document.write( "x = (9+-sqrt(45))/2\r<BR>\n" );
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document.write( "x = (9+sqrt(45))/2 or x = (9-sqrt(45))/2\r<BR>\n" );
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document.write( "x = (9+3*sqrt(5))/2 or x = (9-3*sqrt(5))/2\r<BR>\n" );
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document.write( "x = 7.85410196624969 or x = 1.14589803375031\r<BR>\n" );
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document.write( "Since each dimension is positive, this means that the only solution is approximately x = 7.85410196624969\r<BR>\n" );
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document.write( "Perimeter of the rectangle\r<BR>\n" );
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document.write( "P = 2L + 2W\r<BR>\n" );
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document.write( "P = 2(2x-3) + 2(x-3)\r<BR>\n" );
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document.write( "P = 2(2*7.85410196624969-3) + 2(7.85410196624969-3)\r<BR>\n" );
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document.write( "P = 35.1246117974981\r<BR>\n" );
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document.write( "So the perimeter of the rectangle is approximately 35.1246117974981 units\r<BR>\n" );
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