document.write( "Question 610228: Factor completely. If a polynomial is prime, state this.
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Algebra.Com's Answer #384226 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"-12x%5E2-28x%2B24\" Start with the given expression.\r
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\n" ); document.write( "\n" ); document.write( "\"-4%283x%5E2%2B7x-6%29\" Factor out the GCF \"-4\".\r
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\n" ); document.write( "\n" ); document.write( "Now let's try to factor the inner expression \"3x%5E2%2B7x-6\"\r
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\n" ); document.write( "\n" ); document.write( "Looking at the expression \"3x%5E2%2B7x-6\", we can see that the first coefficient is \"3\", the second coefficient is \"7\", and the last term is \"-6\".\r
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\n" ); document.write( "\n" ); document.write( "Now multiply the first coefficient \"3\" by the last term \"-6\" to get \"%283%29%28-6%29=-18\".\r
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\n" ); document.write( "\n" ); document.write( "Now the question is: what two whole numbers multiply to \"-18\" (the previous product) and add to the second coefficient \"7\"?\r
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\n" ); document.write( "\n" ); document.write( "To find these two numbers, we need to list all of the factors of \"-18\" (the previous product).\r
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\n" ); document.write( "\n" ); document.write( "Factors of \"-18\":\r
\n" ); document.write( "\n" ); document.write( "1,2,3,6,9,18\r
\n" ); document.write( "\n" ); document.write( "-1,-2,-3,-6,-9,-18\r
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\n" ); document.write( "\n" ); document.write( "Note: list the negative of each factor. This will allow us to find all possible combinations.\r
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\n" ); document.write( "\n" ); document.write( "These factors pair up and multiply to \"-18\".\r
\n" ); document.write( "\n" ); document.write( "1*(-18) = -18
\n" ); document.write( "2*(-9) = -18
\n" ); document.write( "3*(-6) = -18
\n" ); document.write( "(-1)*(18) = -18
\n" ); document.write( "(-2)*(9) = -18
\n" ); document.write( "(-3)*(6) = -18\r
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\n" ); document.write( "\n" ); document.write( "Now let's add up each pair of factors to see if one pair adds to the middle coefficient \"7\":\r
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First NumberSecond NumberSum
1-181+(-18)=-17
2-92+(-9)=-7
3-63+(-6)=-3
-118-1+18=17
-29-2+9=7
-36-3+6=3
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\n" ); document.write( "\n" ); document.write( "From the table, we can see that the two numbers \"-2\" and \"9\" add to \"7\" (the middle coefficient).\r
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\n" ); document.write( "\n" ); document.write( "So the two numbers \"-2\" and \"9\" both multiply to \"-18\" and add to \"7\"\r
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\n" ); document.write( "\n" ); document.write( "Now replace the middle term \"7x\" with \"-2x%2B9x\". Remember, \"-2\" and \"9\" add to \"7\". So this shows us that \"-2x%2B9x=7x\".\r
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\n" ); document.write( "\n" ); document.write( "\"3x%5E2%2Bhighlight%28-2x%2B9x%29-6\" Replace the second term \"7x\" with \"-2x%2B9x\".\r
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\n" ); document.write( "\n" ); document.write( "\"%283x%5E2-2x%29%2B%289x-6%29\" Group the terms into two pairs.\r
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\n" ); document.write( "\n" ); document.write( "\"x%283x-2%29%2B%289x-6%29\" Factor out the GCF \"x\" from the first group.\r
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\n" ); document.write( "\n" ); document.write( "\"x%283x-2%29%2B3%283x-2%29\" Factor out \"3\" from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2B3%29%283x-2%29\" Combine like terms. Or factor out the common term \"3x-2\"\r
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\n" ); document.write( "\n" ); document.write( "So \"-4%283x%5E2%2B7x-6%29\" then factors further to \"-4%28x%2B3%29%283x-2%29\"\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So \"-12x%5E2-28x%2B24\" completely factors to \"-4%28x%2B3%29%283x-2%29\".\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"-12x%5E2-28x%2B24=-4%28x%2B3%29%283x-2%29\".\r
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\n" ); document.write( "\n" ); document.write( "Note: you can check the answer by expanding \"-4%28x%2B3%29%283x-2%29\" to get \"-12x%5E2-28x%2B24\" or by graphing the original expression and the answer (the two graphs should be identical).\r
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\n" ); document.write( "If you need more help, email me at jim_thompson5910@hotmail.com\r
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