document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=610070>Question 610070</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find an equation of the line L that passes through the point <BR>\n" );
document.write( "(&#8722;2, 4)<BR>\n" );
document.write( " and satisfies the given condition. (Let x be the independent variable and y be the dependent variable.)<BR>\n" );
document.write( "L is perpendicular to the line <BR>\n" );
document.write( "2x + 5y = 10 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #384183 by </B><A HREF=/tutors/aboutme.mpl?userid=flame8855><B>flame8855(424)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=flame8855><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=flame8855><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=384183\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L : 5y = -2x + 10<BR>\n" );
document.write( "y = -2/5x +2 <BR>\n" );
document.write( "slope = -2/5<BR>\n" );
document.write( "aa' =-1<BR>\n" );
document.write( "a' = 5/2\r<BR>\n" );
document.write( "\n" );
document.write( "y-4/x+2 = 5/2<BR>\n" );
document.write( "y-4 = 5/2x +5<BR>\n" );
document.write( "y = 5/2x +9 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );