document.write( "Question 609723: Write and Solve an Equation, inequality, or system of equations to answer the question.\r
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document.write( "Two Sisters left at the same time to travel home. Susanna drove at 65 miles per hour and started 9 miles farther from home than Rachel. Rachel drove at 55 miles per hour. They reached home at the same time. How far was each girl from home? \n" );
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Algebra.Com's Answer #384114 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Two Sisters left at the same time to travel home. \n" ); document.write( "Susanna drove at 65 miles per hour and started 9 miles farther from home than Rachel. \n" ); document.write( " Rachel drove at 55 miles per hour. \n" ); document.write( " They reached home at the same time. \n" ); document.write( " How far was each girl from home? \n" ); document.write( "; \n" ); document.write( "Let d = Rachel's distance from home \n" ); document.write( "then \n" ); document.write( "(d+9) = Susanna's distance \n" ); document.write( ": \n" ); document.write( "Write a time equation; time = dist/speed \n" ); document.write( "Their travel times are equal. \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( "cross multiply \n" ); document.write( "65d = 55(d+9) \n" ); document.write( "65d = 55d + 495 \n" ); document.write( "65d - 55d = 495 \n" ); document.write( "10d = 495 \n" ); document.write( "d = 495/10 \n" ); document.write( "d = 49.5 mi, R's distance \n" ); document.write( "then \n" ); document.write( "49.5 + 9 = 58.5 mi, S's distance \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "See if that checks out; find the time of each; they should be equal. \n" ); document.write( "49.5/55 = .9 hrs \n" ); document.write( "58.5/65 = .9 hrs \n" ); document.write( " \n" ); document.write( " |