document.write( "Question 610069: Given belly button height (x) of students is normally distributed with a mean of 100cm and a standard deviation of 20cm. Find P(90 < x < 120).
\n" ); document.write( "Given that X the random variable belly button height (x) has a mean of 100 cm and standard deveiation of 20cm. Find belly button height x, such that P(belly button height [X] <=x) = 0.025. \n" ); document.write( "
Algebra.Com's Answer #384110 by stanbon(75887)\"\" \"About 
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Given belly button height (x) of students is normally distributed with a mean of 100cm and a standard deviation of 20cm. Find P(90 < x < 120).
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\n" ); document.write( "z(90) = (90-100)/20 = -10/20 = -1/2
\n" ); document.write( "z(120) = (120-100)/20 = 1
\n" ); document.write( "P(90 < x < 120) = P(-1/2 < z < 1) = 0.7263
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\n" ); document.write( "\n" ); document.write( "Given that X the random variable belly button height (x) has a mean of 100 cm and standard deveiation of 20cm. Find belly button height x, such that
\n" ); document.write( "P(belly button height [X] <=x) = 0.025.
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\n" ); document.write( "Find the z-value with a left tail of 0.025
\n" ); document.write( "z = invNorm(0.025) = -1.96
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\n" ); document.write( "Find \"x\" using x = zu + u
\n" ); document.write( "x = -1.96*20 + 100
\n" ); document.write( "x = 60.8 in
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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