document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=610037>Question 610037</A>: <I><SPAN STYLE=\"word-break: break-all;\"> . The sum of the reciprocals of two consecutive positive odd integers is 16/63. Find the integers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #384094 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=384094\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The sum of the reciprocals of two consecutive positive odd integers is 16/63. Find the integers.<BR>\n" );
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document.write( "1st: 2x-1<BR>\n" );
document.write( "2nd: 2x+1<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "1/(2x-1) + 1/(2x+1) = 16/63<BR>\n" );
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document.write( "Multiply thru by 63*(2x-1)(2x+1) to get:<BR>\n" );
document.write( "63(2x+1) + 63(2x-1) = 16(4x^2-1)<BR>\n" );
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document.write( "126x + 63 + 126x - 63 = 64x^2 - 16<BR>\n" );
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document.write( "64x^2 - 252x - 16 = 0<BR>\n" );
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document.write( "Divide thru by 4 to get:<BR>\n" );
document.write( "16x^2 - 63x - 4 = 0<BR>\n" );
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document.write( "16x^2-64x+x-4 = 0<BR>\n" );
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document.write( "16x(x-4)+(x-4) = 0<BR>\n" );
document.write( "(x-4)(16x+1) = 0<BR>\n" );
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document.write( "x = 4 or x = -1/16<BR>\n" );
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document.write( "If x = 4 <BR>\n" );
document.write( "2x-1 = 7<BR>\n" );
document.write( "2x+1 = 9<BR>\n" );
document.write( "=================<BR>\n" );
document.write( "cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "================= </SPAN>\n" );
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