document.write( "Question 610020: A random sample of movie lengths in minutes is as follows:
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document.write( "110 95 131 257 118 153
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document.write( "8. Find the standard deviation.
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document.write( "9. Are any of these movie lengths considered unusual in the sense of our textbook?
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document.write( "Explain. Does this differ with your intuition? Explain. \n" );
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Algebra.Com's Answer #384091 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A random sample of movie lengths in minutes is as follows: \n" ); document.write( "110 95 131 257 118 153 \n" ); document.write( "8. Find the standard deviation. \n" ); document.write( "Ans: 58.74 \n" ); document.write( "-------------------------------------- \n" ); document.write( "9. Are any of these movie lengths considered unusual in the sense of our textbook? \n" ); document.write( "Explain. \n" ); document.write( "Sample mean = 114 \n" ); document.write( "2 standard deviations is the limit for \"unusual\": \n" ); document.write( "2 standard deviations below is negative \n" ); document.write( "2 standard deviations above is 114 + 2*58.74 = 231.48 \n" ); document.write( "--- \n" ); document.write( "So 257 minutes is \"unusual\" movie length. \n" ); document.write( "=========================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "==========================\r \n" ); document.write( "\n" ); document.write( "Does this differ with your intuition? Explain. \n" ); document.write( "No; most movies are right around 2 hours or 120 minutes. \n" ); document.write( "========================================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "============= \n" ); document.write( " \n" ); document.write( " |