document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=609927>Question 609927</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a basketball player makes 70% of the free throws he shoots. if he tries 13 throws what is the probability that he will make more than five throws? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #384037 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=384037\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This problem involves binomial probabilities<BR>\n" );
document.write( "The binomial probability distribution is written as<BR>\n" );
document.write( "P(x) = C(n,x)*p^x*(1-p)^(n-x) where n = the number of trials, x = the number of successes, and p is the probability of success<BR>\n" );
document.write( "More than 5 throws means we need to compute the probability of 6 or more<BR>\n" );
document.write( "P(6 or more) = 1 - P(5 or less)<BR>\n" );
document.write( "P(5 or less) = P(5) + P(4) + ... P(0)<BR>\n" );
document.write( "P(5) = C(13,5)*0.7^5*0.3^8 = 0.0142<BR>\n" );
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document.write( "Adding up all the probabilities and subtracting from 1, we get:<BR>\n" );
document.write( "P(6 or more) = 1 - 0.018 = 0.982 </SPAN>\n" );
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